VCE Chemistry Unit 4 exam 2011 analysis
By Heath McGregor on Nov 14, 2011 in VCE Chemistry, VCE Exams, VCE Resources
Hi all, congrats on completing the VCE Chemistry Unit 4 exam for 2011. What did you think of the paper? What was hard? What was easy? How do you think you went? Let us know your thoughts and comments below (please keep them clean!)…cheers
(8 votes, average: 4.13 out of 5)
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UmOk?
the HCOONa was the HCOO-
btw Kevin ur absolutely right….but because of the assumptions they stated at the beginning of the question u had to ignore that
yep…vcaa rewards exam technique more than understanding :
@UmOk?, if you got an A+ on midyear and found this one hard, then I am screwed!!! It was very tough… I walked out feeling confident then came on here …
@ UmOK totally agree with you! I also got an A+ in midyear but that question especially confused me on this one!
You assume that [HCOONa] = [HCOO-] because when the in a solution HCOONa will exist as HCOO- and Na+ ions. Therefore you can assume the that they two equal each other.
yeh i thought so to. a lot more theory than expected
i dont remember my answer for the acid/ph question but i did the same as the people who got 3.05, which i think i rounded to 3.1 out of memory. it said the the [HCOO-] was the initial concentration so im guessing you just use the [HCOONa] and exclude the other value which is the same as [H30+]. i fell into the trap of using Cu2+ and got the 600 something minutes as my answer
but oh well, im hoping for a B+ like mid years. I’d be happy with that.
For the last question I thought the point of Cu+ was to get rid of them by adding excess KOH(I think) as C+ reacts with OH- ions. By doing this you improve the quality of the copper being plated which you get from the Cu2+ ions as all the Cu+ ions would have reacted with the OH- ions.
That’s what I thought it was hence I got 629 mins.
Dont worry about it!!! nobody can really tell what they’re going to get on the exam until results come out!! theres no point in predicting scores etc because everything is relative!!
Heck! there’s no point even discussing answers! Our exams have been submitted to VCAA and no matter what we do we can’t change what we wrote!!
funny thing though.. as i was in that exam.. i dont know why but i thought we finished at 10:15 not 10:45… so when it was like 10 o clock i was almost in tears because i had like 4 pages left!! lol!! and then 1015 came and im like “oh sh** lol still got half and hour”!! haha
When my supervisor collected my paper shes like to me “You ok? Stress less!!” haha!! the faces i must have been making during that exam!!! lol
and i have physics tomorrow!! the assessors going to think im cheating when i use the right hand slap/ grip rule
haha
You are right on both accounts -71.7 and 315
What did people get for the question that you had to find the Coulombs?
@confused. They mentioned that the only solutions in the electrolyte were copper(I)cyanide, KOH and one other ionic compund. There was no mention of Cu 2+ and therefore you need to assume all copper ions in the cell have a plus one charge. Its like imagining the cell contained Fe 3+. Can you say that the cathode reaction involves Fe 2+ when it is not present in the electrolyte?
that exam was haaaaaaaarrrrrrrrrrrdddddddd + longgggggggggg!
i just want to cry :’(
For that pH question i got 3. something but as my final answer i just wrote
pH=3
without rounding to two significant figures. Will i be penalised?
I also got the pH as 2.17. If they put the methanoate stuff in the question why would we have to ignore it? I think you had to put it in, just as a way for vcaa to confuse you. And you used Cu+ not 2+ coz it’s in reference to the rest of the question, but you’d get consequential marks.
If i got A+ in my sacs for unit 3 and A for unit for sacs, but i did terrible in exams i got C mid year and possibly another C this exam, what should i expect as a raw score?
Please help!
@selena
Depending on the rest of your cohort and whether they did so your SAC grades don;t get put down, around about 29-32
WHAT WAS THE UQUATION FOR THEM OXYGEN TO OXIDE IONS WHUUUUUT!!
Mike the equation was O2(g) + 4e > 2O2^-(g)
any solutions yet?
solutions that actually open?? solutions pleaseeeeee???????????